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Here-strings in bash are implemented via temporary files, usually in the format /tmp/sh-thd., which are later unlinked, thus making them occupy some memory space temporarily but not show up in the list of /tmp directory entries, and effectively exist as anonymous files, which may still be referenced via file descriptor by the ... bash - What is the purpose of "&&" in a shell command? - Stack Overflow What is the operator =~ called? I'm not sure it has a name. The bash documentation just calls it the =~ operator. Is it only used to compare the right side against the left side? The right side is considered an extended regular expression. If the left side matches, the operator returns 0, and 1 otherwise. Why are double square brackets required when running a test? Because =~ is an operator of ... For understanding bash code it is usually very helpful to set the -x option: set -x # within a script / function or when calling a script: bash -vx ./script.sh With loops this is a little less helpful. But you can always take the first part of the command and do this: echo for url in $(cat example.txt) That shows you what happens there (at least the result). This feature is called "command ... bash - What does $ ( ... ) mean in the shell? - Unix & Linux Stack Exchange Furthermore, when you use bash -c, behavior is different than if you run an executable shell script, because in the latter case the argument with index 0 is the shell command used to invoke it. The reason is that Bash is untyped. The -eq causes the strings to be interpreted as integers if possible including base conversion: ... And 0 if Bash thinks it is just a string: ... So [[ "yes" -eq "no" ]] is equivalent to [[ 0 -eq 0 ]] Last note: Many of the Bash specific extensions to the Test Constructs are not POSIX and therefore may fail ... I am trying to understand how the logical operator precedence works in bash. For example, I would have expected, that the following command does not echo anything. true || echo aaa && echo... bash - Precedence of the shell logical operators &&, || - Unix & Linux ... In general, in bash and other shells, you escape special characters using \. So, when you use echo foo >\> what you are saying is "redirect to a file called > ", but that is because you are escaping the second >. It is equivalent to using echo foo > \> which is the same as echo foo > '>'. So, yes, as Sirex said, that is likely a typo in your book.
